Aug 152013
 


Time: 3 hours

Full Marks: 75

Pass Marks: 27

Section A (Botany)

1. Answer any seven questions in very short. (1 × 7 = 7)

a. Write the function of xylem.
b. Name the components of a nucleotide.
c. Give one example of polygenic inheritance.
d. Define genetic code.
e. What is polyploidy?
f. Mention two importance of vegetative propagation.
g. Give two examples of entomophilus plants.
h. Define genetic engineering.
i. Define tissue culture.
j. What is the main source of green manures?

2. Answer any five questions in brief. (3 × 5 = 15)

a. Give the well-labelled diagram of monocot embryo. (Description is not required)
b. What are the differences between dicot stem and monocot stem?
c. Explain the types of transpiration in plants.
d. Differentiate between phenotype and genotype.
e. What did you understand by Mendel’s 9:3:3:1 ratio?
f. Differentiate between self and cross fertilization.
g. Show with the diagrams the development of dicot embryo. (No description required)
h. Mention the applications of genetic engineering.

3. What is secondary growth? Discuss the activity of cambium in secondary growth of dicot stem. (7.5)

OR

Describe the light dependent steps of photosynthesis.

4. “DNA is the hereditary material”, explain it with an experiment. (8)

Section B (Zoology)

1. Answer any seven questions in very short. (1 × 7 = 7)

a. In which kind of animal tissue you find the mast cells.
b. Name the two sex linked diseases in human.
c. Define gametogenesis.
d. Name any two enzymes which are responsible for protein digestion.
e. Define the term ‘deamination’.
f. Which part of human brain is the centre of intelligence?
g. Name the causative agent of typhoid fever.
h. What does ISD cause?
i. What is the role of surrogate mother in test tube baby?
j. Differentiate heterograft and autograft.

2. Answer any five questions in brief. (3× 5 = 15)

a. Describe the structure of areolar tissue.
b. If a red-eyed male Drosophila is mated with a white-eyed female, what will be the phenotype of male and female in F1 progeny?
c. How is the notochord formed in the embryo of frog?
d. What is vitamin? Mention the functions of fat-soluble vitamins.
e. Draw a labelled sketch of internal structure of human kidney.
f. What will be the problems of over human population? Suggest some measures to control over population.
g. Define amniocentesis. Mention its positive and negative effects.

3. Explain the structure and function of human brain. (8)

OR

Explain the respiratory organs of human being.

4. What are communicable disease? Discuss the causative agents, symptoms, effects and control measures of any one communicable disease you have studied. (7.5)

Aug 112013
 



motion of electronLet us consider that, an electron of mass ‘m’ moves with initial horizontal velocity ‘vx‘. While the electron enters the electric field between the parallel plates, it is attracted towards the upper positive plate.

The electrostatic force with which electron is attracted upwards is given by,
Fe = eE
or, Fe = eVd …. (i)

Let ‘a’ be the acceleration produced in an electron while it moves upwards.

Then, from Newton’s second law of motion,

F = ma …. (ii)

From equations (i) and (ii), we get,

ma = eVd
or, a = eVmd …. (iii)

Let at any time ‘t’, electron is at a point ‘P’ and X and Y be its horizontal and vertical displacement.

In horizontal displacement,

X = ut + 12at2 (Horizontal velocity remains constant.)

or, X = vxt
or, t = Xvx …. (iv)

Again, in vertical displacement,

Y = ut + 12at2

Since the initial velocity is zero,

Y = 12at2
Now, substituting the values of ‘a’ and ‘t’ in the above equation,
Y = eVX22mdvx2

Here, Y = kX2
or, X2 = 2mdvxYeV
∴ X2 = bY

This is the equation of parabola.

Hence, the path followed by electron in electric field is parabolic. Let ‘D’ be the length of the plate and ‘T’ be the time taken to travel the distance equal to the length of the plate.

T = DVx …. (v)

The electron moves in a straight line after leaving the plates. Let ‘θ’ be the angle of deflection with respect to vx after leaving the plate by an electron.
The vertical component of velocity vy is given by,
vy = u + aT
Since u = 0,
vy = eVDmdvx

Now, the angle of deflection is given by,

tanθ = Vy/vx

or, θ = tan-1(eVD/mdvx2)

Again, the resultant velocity is given by, vR = √(vx2 + vy2)

= √ (vx2 + e2V2D2/m2d2vx2)

Increase in Kinetic Energy

Initial Kinetic Energy (Ei) = 1/2mvx2
Final Kinetic Energy (Ef) = 1/2mvR2

= 1/2mvx2 + 1/2mvy2

Hence, the increase in kinetic energy is given by,

E = Ef – Ei
= 1/2mvx2 + 1/2mvy21/2mvx2
= 1/2mvy2
= 1/2×me2V2D2/m2d2vx2
= 1/2×e2V2D2/md2vx2